20t^2+560t=11760

Solution for 20t^2+560t=11760 equation:

20t^2+560t=11760

We move all terms to the left:

20t^2+560t-(11760)=0

a = 20; b = 560; c = -11760;
Δ = b2-4ac
Δ = 5602-4·20·(-11760)
Δ = 1254400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1254400}=1120$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(560)-1120}{2*20}=\frac{-1680}{40}
=-42
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(560)+1120}{2*20}=\frac{560}{40}
=14
$